Problem 6: Sum square difference

Q)The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

solution:

Java code:

public class Prob6 {

 
 public static void main(String[] args) {
  
  System.out.println(squaresOfSum(100)-sumOfSquares(100));

 }

 
 public static long sumOfSquares( int b)
 {
  long sum =0;
  for(int i =1 ; i <= b; i++)
  {
   sum =sum + (i*i);
  }
  
  return sum;
 }
 
 public static long squaresOfSum( int b)
 {
  long sum =0;
  for(int i =1 ; i <= b; i++)
  {
   sum =sum + i;
  }
  
  return sum*sum;
 }
 
 
}