The sequence of triangle numbers is generated by adding the natural numbers. So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28. The first ten terms would be:
1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ...
Let us list the factors of the first seven triangle numbers:
1: 1
3: 1,3
6: 1,2,3,6
10: 1,2,5,10
15: 1,3,5,15
21: 1,3,7,21
28: 1,2,4,7,14,28
We can see that 28 is the first triangle number to have over five divisors.
What is the value of the first triangle number to have over five hundred divisors?
Solution:
java code:
Solution:
java code:
public class Prob12 {
public static void main(String[] args) {
int DivCount =0;
long i =76576499;
while (DivCount <= 500)
{ i++;
if(CheckTriangular(i))
{
DivCount=divisorCount(i);
}
}
System.out.println(i);
}
public static boolean CheckTriangular(long a)
{
long A81= 8*a+1;
long sqrt =(long)Math.sqrt(A81);
if (sqrt*sqrt == A81)
return true;
else
return false;
}
public static int divisorCount(long a)
{
int count =0;
for(long i = 1; i <= a; i++ )
{
if(a%i ==0)
count++;
}
return count;
}
}
why did u take i=76576499?
ReplyDeleten why u took A81=8*a+1?
pls explain the logic...
by the way ur programs r very easy to understand for a begineer like me...
thnx a lot..