215 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 21000?
Solution:
Again I've used BigInteger because 21000 doesn't fit inside long.
Here's the java code
import java.math.BigInteger;
public class Prob16 {
public static void main(String[] args) {
int sum =0;
int digit;
BigInteger a = new BigInteger("1");
BigInteger b = new BigInteger("2");
for(int i = 1 ; i <= 1000 ; i++ )
{
a = a.multiply(b);
}
String A = a.toString();
for(int i =0 ; i < A.length();i++)
{
digit = A.charAt(i) - '0';
sum = sum + digit;
}
System.out.println(sum);
}
}
why is that
ReplyDeletedigit = A.charAt(i) - '0';
I mean 0
I am converting each Ascii character value Numerical value, i.e to convert '1' to 1.
Deletethe ASCII value of '1' is 49 to convert it to Numerical 1, I am subtracting the ASCII value of the first digit, i,e '0' which has an ASCII value of 48,
Digit = '1' - '0';
which is similar to 49 - 48.